Refactor times inverse of sqrt 2 calculation (#21293)
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a0ea7a6b17
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9b3ac793bc
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@ -25,11 +25,16 @@
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#include "mousekey.h"
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static inline int8_t times_inv_sqrt2(int8_t x) {
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// 181/256 is pretty close to 1/sqrt(2)
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// 0.70703125 0.707106781
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// 1 too small for x=99 and x=198
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// This ends up being a mult and discard lower 8 bits
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return (x * 181) >> 8;
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// 181/256 (0.70703125) is used as an approximation for 1/sqrt(2)
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// because it is close to the exact value which is 0.707106781
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const int16_t n = x * 181;
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const uint16_t d = 256;
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// To ensure that the integer result is rounded accurately after
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// division, check the sign of the numerator:
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// If negative, subtract half of the denominator before dividing
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// Otherwise, add half of the denominator before dividing
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return n < 0 ? (n - d / 2) / d : (n + d / 2) / d;
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}
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static report_mouse_t mouse_report = {0};
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