39 lines
1.1 KiB
Python
39 lines
1.1 KiB
Python
|
#!/usr/bin/python3
|
||
|
|
||
|
import numpy as np
|
||
|
from operator import itemgetter
|
||
|
|
||
|
def s2p_to_narray(file):
|
||
|
""" prebere s2p file v narray. STOLPCI --> VRSTICE!!! """
|
||
|
return np.loadtxt(file, comments=('!','#')).T
|
||
|
|
||
|
def narray_to_s(narray):
|
||
|
""" prebran s2p narray posortiram po s parametrih.
|
||
|
pri tem upostevam vrstni red:
|
||
|
f s11 s21 s12 s22, kjer sta za vsak s parameter
|
||
|
dve vrstici: realni in imaginarni del """
|
||
|
keys = ["s{}{}".format(j,i) for i in range(1,3) for j in range(1,3)]
|
||
|
s = {}
|
||
|
for i in range(4):
|
||
|
s[keys[i]] = narray[(2*i+1),:]+1j*narray[(2*i+2),:]
|
||
|
s['f'] = narray[0,:]
|
||
|
return s
|
||
|
|
||
|
def s_to_eps(s, L):
|
||
|
""" izracunam eps in tand iz s parametrov in dolzin """
|
||
|
s11, s21, s12, s22, f = itemgetter(*s.keys())(s)
|
||
|
|
||
|
X = (s11**2 - s21**2 + 1)/2/s11
|
||
|
G = X + np.sqrt(X**2 - 1)
|
||
|
if np.abs(G) > 1:
|
||
|
G = X - np.sqrt(X**2 - 1)
|
||
|
P = (s11 + s21 - G)/(1-(s11+s21)*G)
|
||
|
Lambda2 = - (1/2/np.pi/L * np.log(1/P))**2 #izmisli resitev za korene kompleksnega logaritma
|
||
|
# argument korena mora biti 2*pi*n, kjer je n=L/lambda_g
|
||
|
|
||
|
return
|
||
|
|
||
|
a=s2p_to_narray('20.s2p')
|
||
|
b = narray_to_s(a)
|
||
|
s_to_eps(b,0,0,0)
|