35 lines
675 B
Python
35 lines
675 B
Python
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#!/usr/bin/env python3
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# quick and dirty solution
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from math import sqrt, log10
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def main(n):
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a = 2
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nums = []
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while len(nums) < n or a < nums[-1]**(1.0/pw):
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an, pw = check(a, nums*(len(nums)>=n))
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a += 1
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if an:
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nums += an
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nums = sorted(nums)[:n]
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return nums[-1]
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def check(a, nums):
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pw = int((a/9) * (1/log10(a)))
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pw = 2 if pw<2 else pw
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n = a**pw
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r = []
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while len(str(n)) <= a and (not nums or n < nums[-1]):
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if digsum(n) == a:
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r.append(n)
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n *= a
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return r, pw
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def digsum(n):
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return sum(map(int, str(n)))
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#print(main(2))
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#print(main(10))
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print(main(30))
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